• # question_answer (a) Find the amount of Rs. 50000 after 2 years compounded annually. The rate of interest being 8% p.a. during the first year and 9% p.a. during the second year. Also, find the compound interest. (b) If (a) decreased value $=P{{\left( 1-\frac{R}{100} \right)}^{n}}$   and (b) depreciated value $=P{{\left( 1+\frac{R}{100} \right)}^{n}}$ then select right answer.

 (a) Here P=' 50000, ${{R}_{1}}$ = 8% p.a. and ${{R}_{2}}$ = 9% p.a Since,        $A=P\left( 1+\frac{{{R}_{1}}}{100} \right)\left( 1+\frac{{{R}_{2}}}{100} \right)$ $=50000\times \left( 1+\frac{8}{100} \right)\left( 1+\frac{9}{100} \right)$ $=50000\times \frac{27}{25}\times \frac{109}{100}$ Amount =Rs.58860 Therefore                  $C.I.\text{ }=\text{ }A\text{ }-\text{ }P$ $=58860-50000$ =Rs. 8860 (b) (a) is right answer.