8th Class Mathematics Sample Paper Mathematics Sample Paper - 3

  • question_answer             The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.

    Answer:

    Let the sides of two squares are a and b respectively.
    4a = 40 and 4b = 96
    \[\therefore \]      a = 10 m and b = 24 m
    Given,                                                                                                                                                              
    The perimeter of another square = Sum of area of two squares.
    = Area of Ist square + Area of IInd square
    \[={{a}^{2}}+{{b}^{2}}\]
    \[={{\left( 10 \right)}^{2}}+{{\left( 24 \right)}^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\]
    =100 + 576
    = 676 m2                                                                                                                                              
    Hence, the perimeter of another square = 676 m. 


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