• # question_answer             The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.

 Let the sides of two squares are a and b respectively. 4a = 40 and 4b = 96 $\therefore$      a = 10 m and b = 24 m Given, The perimeter of another square = Sum of area of two squares. = Area of Ist square + Area of IInd square $={{a}^{2}}+{{b}^{2}}$ $={{\left( 10 \right)}^{2}}+{{\left( 24 \right)}^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~$ =100 + 576 = 676 m2 Hence, the perimeter of another square = 676 m.