question_answer

Find:

(a) \[6\div 5\frac{1}{3}\]

(b) \[7\div 2\frac{4}{7}\]

Answer:

(a) We have \[6\div 5\frac{1}{3}=6\div \left( \frac{5\times 3\times 1}{3} \right)\]

\[=6\div \left( \frac{15+1}{3} \right)=6\div \frac{16}{3}\]

\[=6\times \frac{3}{16}\]

\[\left[ \because reciprocal\text{ }of\frac{16}{3}is\frac{6}{16} \right]\]

\[=\frac{18}{16}=\frac{9}{8}=1\frac{1}{8}\]

[Dividing numerator and denominator by 2]

(b) Do same as above.

\[7\div 2\frac{4}{7}=2\frac{13}{18}\]