Answer:
\[x+y=-\frac{3}{16}+\frac{1}{9}\] \[=\frac{-3\times 9+1\times 16}{144}\] [\[\because \]LCM of 16 and 9 is 144] \[=\frac{-27+16}{144}=\frac{-11}{144}\] \[y+x=\frac{1}{9}+\frac{-3}{16}\] \[=\frac{1}{9}-\frac{3}{16}\] \[=\frac{16\times 1-9\times 3}{144}\] \[=\frac{16-27}{144}=-\frac{11}{144}\] \[\Rightarrow \] \[x+y=y+x.\]
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