question_answer

Sunita is half the age of her mother Geeta. Find their ages

(i) after 4 years?

(ii) before 3 years?

Answer:

Let the age of Sunita?s mother = 2x years

Then, according to the question

Geeta?s age \[=\frac{2x}{2}=x\]

[half of her mother?s age]

(i) Since, in the after 4 years, present age is added in given years.

\[\therefore\]Sunita?s age \[=(x+4)\]  years

Her mother?s age \[=(2x+4)\]  years

(ii) Since, in the before years, given year is subtracted from present age.

\[\therefore\]Sunita?s age \[=(x-3)\]  years and her mother?s age \[=(2x-3)\] years.