Answer:
Perimeter of the top of the table \[=2\times\] (length + breadth) \[=2\times (2.25\,\,\text{m}+1.5\,\,m)\] \[=2\times 3.75\,\,\text{m}\] \[\left( \because \,1\,\text{cm}=\frac{1}{100}\text{m} \right)\] \[=7.50\,\,\text{cm}\]
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