(a) Find the population in 2001. |
(b) What would be its population in 2005? |
Answer:
(a) Here A = 54000, R = 5%, n = 2 year, \[\therefore \] P =? \[A=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[54000=P{{\left( 1+\frac{5}{100} \right)}^{2}}\] \[=P{{\left( \frac{21}{20} \right)}^{2}}\] \[\Rightarrow \,\,\] \[P=\frac{54000\times 20\times 20}{21\times 21}\] = 48980 (approx.) \[\therefore \] Population in 2001 was 48980. (b) Here, P = 54000, R = 5% p.a., n = 2 years \[A=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[=54000{{\left( 1+\frac{5}{100} \right)}^{2}}\] \[=54000\times \frac{21}{20}\times \frac{21}{20}\] = 59535 Hence, population in 2005 would be 59535.
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