question_answer

Draw a rhombus ABCD such that AC = 6.6 cm, BD = 5.6 cm.

Answer:

Steps of Construction :

(a)  Draw a line segment AC = 6·6 cm.

(b) Draw perpendicular bisector XY of AC, which meets AC at M.

(c) With centre M take the radius =\[=\frac{1}{2}\times 5.6\]cm i.e., 2·8 cm, draw arcs to intersect XY at B and D.

(d) Joint AB, BC, CD and AD.

Thus, ABCD is the required rhombus.