Answer:
We know that, \[{{\cos }^{2}}\alpha +{{\cos }^{2}}\beta +{{\cos }^{2}}\gamma =1\] Here, \[\alpha =\frac{\pi }{3}\]and \[\beta =\frac{\pi }{4}\] So, \[{{\cos }^{2}}\frac{\pi }{3}+{{\cos }^{2}}\frac{\pi }{4}+{{\cos }^{2}}\gamma =1\] \[\Rightarrow \] \[{{\left( \frac{1}{2} \right)}^{2}}+{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}+{{\cos }^{2}}\gamma =1\] \[\Rightarrow \] \[\frac{3}{4}+{{\cos }^{2}}\gamma =1\] \[\Rightarrow \] \[{{\cos }^{2}}\gamma =1-\frac{3}{4}=\frac{1}{4}\Rightarrow \cos \gamma =\frac{1}{2}\] \[\therefore \] \[\gamma =\frac{\pi }{3}\]
You need to login to perform this action.
You will be redirected in
3 sec