Answer:
We have, Now, P (all 3 balls are of same colour) \[=\frac{5}{13}\times \frac{7}{13}\times \frac{6}{11}+\frac{8}{13}\times \frac{6}{13}\times \frac{5}{11}=\frac{210}{1859}+\frac{240}{1859}=\frac{450}{1859}\]
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