Answer:
Let the required number = x According to problem, \[{{\left( \frac{-3}{2} \right)}^{-3}}\div x={{\left( \frac{9}{4} \right)}^{-2}}\] or \[{{\left( \frac{2}{-3} \right)}^{-3}}\div x={{\left( \frac{4}{9} \right)}^{2}}\] or \[\frac{8}{-27}\times {{x}^{-1}}=\frac{16}{81}\] \[\left[ \because \,\,\frac{1}{{{x}^{a}}}={{x}^{-a}} \right]\] or \[{{x}^{-1}}=\frac{16}{81}\times \frac{-27}{8}\] or \[{{x}^{-1}}=\frac{-2}{3}\] or \[\frac{1}{x}=\frac{-2}{3}\] or \[x=\frac{-3}{2}\] Hence, required number \[=\frac{-3}{2}\]
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