Answer:
\[=12(x+3)\] \[12x+36\] \[12x=2\times 2\times 3\times x\] \[36=2\times 2\times 3\times 3\] The common factors of the three terms are 2, 2 and 3. Therefore, \[12x+36=(2\times 2\times 3\times x)+(2\times 2\times 3\times 3)\] \[=2\times 2\times 3\text{ }\left( x+5 \right)\]
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