A) \[a=2\]
B) \[a=3\]
C) \[a=1\]
D) \[a=0\]
Correct Answer: C
Solution :
[c] \[\because A,B,C\]be collinear, then \[\Delta ABC=0\] \[-12+4\left( 4-a \right)=0\] \[4-a=\frac{12}{4}=3\] \[a=4-3=1\] Hence, option [c] is correct.You need to login to perform this action.
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