A) \[\frac{8}{15}\]
B) \[\frac{5}{18}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: B
Solution :
[b] Total no. of ways of selecting 2 good apples \[{{=}^{6}}{{C}_{2}}=\frac{\left| \!{\nderline {\, 6 \,}} \right. }{\left| \!{\nderline {\, 2 \,}} \right. .\left| \!{\nderline {\, 4 \,}} \right. }=\frac{6\times 5}{2}\] \[=15\And \]total no. of ways so that at least one of the two selected apples is good \[{{=}^{6}}{{C}_{1}}{{\times }^{9}}{{C}_{1}}=6\times 9\] = 54 Hence the required probability \[=\frac{15}{54}=\frac{5}{18}\]Hence, option is correct.
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