A) A
B) 2A
C) \[A+1\]
D) None of these
Correct Answer: A
Solution :
[a] \[\because {{A}^{2}}=I\] Multiplying \[{{A}^{-1}}\]on both sides, we have \[\because A.{{A}^{-1}}=I.{{A}^{-1}}\] \[\Rightarrow A.\left( A\text{ }{{A}^{-1}} \right)={{A}^{-1}}\] [\[\therefore A\] is a square matrix] \[\Rightarrow A.I={{A}^{-1}}\] \[\Rightarrow A={{A}^{-1}}\] Hence, option [a] is correct.You need to login to perform this action.
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