A) Less than 0.1% of 22.4 litres
B) About 10% of the volume of the container of 22.4 litres
C) Between 10% to 20% of 22.4 litres
D) Between 2% to 5% of 22.4 litres
Correct Answer: A
Solution :
One mole of water \[=18g=18\text{ }c{{m}^{3}}\] (density of water \[=1g/c{{m}^{3}}\] Volume of one mole of water vapours = 22.4 L \[=22400\text{ }c{{m}^{3}}\] Percentage volume actually occupied by the water molecules \[=\frac{18}{22400}\times 100=\frac{9}{112}=\frac{9}{112}<0.1%\]
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