JEE Main & Advanced Sample Paper JEE Main Sample Paper-8

  • question_answer
    A current of 4A produces a deflection of \[30{}^\circ \] in the galvanometer. The figure of merit is

    A)  6.5 A/rad                           

    B)  7.6 A/rad

    C)  7.5 A/rad                           

    D)  8.0 A/rad

    Correct Answer: B

    Solution :

     Here \[I=4A\] \[\theta ={{30}^{o}}={{\left( \frac{30\times \pi }{180} \right)}^{c}}=\frac{\pi c}{6}\] Now, \[k=\frac{I}{\theta }=\frac{4}{\left( \frac{\pi }{6} \right)}=\frac{4\times 6\times 7}{22}=\frac{2\times 6\times 7}{11}\] \[=\frac{84}{11}=7.6\text{A/rad}\]


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