A) Conc. \[HCl+KMn{{O}_{4}}\]
B) \[NaCl+\] conc. \[{{H}_{2}}S{{O}_{4}}\]
C) \[NaCl+Mn{{O}_{2}}\]
D) \[NaCl+\] conc. \[HN{{O}_{3}}\]
Correct Answer: A
Solution :
\[16HCl+2KMn{{O}_{4}}\to 2KCl+2MnC{{l}_{2}}+5C{{l}_{2}}\uparrow \]\[+8{{H}_{2}}O\]
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