A) \[3.32\times {{10}^{-15}}m\]
B) \[3.3\times {{10}^{-18}}m\]
C) \[3.7\times {{10}^{-16}}m\]
D) \[1.22\times {{10}^{-15}}m\]
Correct Answer: B
Solution :
\[\lambda =\frac{h}{m\upsilon }\] \[=\frac{6.6\times {{10}^{-34}}\times 6.022\times {{10}^{23}}\times 100}{4.0026\times 3\times {{10}^{8}}\times 10}=3.3\times {{10}^{-18}}m\]
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