A) \[100\,\Omega \]
B) \[169\,\Omega \]
C) \[167\,\Omega \]
D) \[200\,\Omega \]
Correct Answer: C
Solution :
\[{{Z}_{\upsilon }}=6\] volt, \[{{V}_{i}}=10\,\] volt V across \[{{R}_{s}}=10-6=4\,\] volt Current through \[{{R}_{s}}={{I}_{\,z}}+{{I}_{L}}\] \[=(5\times 4)mA+4\,mA=24\,mA\] \[\therefore \,\,{{R}_{s}}=\frac{{{V}_{S}}}{{{I}_{S}}}=\frac{4}{24\times {{10}^{-3}}}=\frac{1}{6}\times {{10}^{3}}\] \[=0.1\overline{\,66}\times {{10}^{3}}=167\,\Omega \]You need to login to perform this action.
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