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JEE Main & Advanced Sample Paper JEE Main Sample Paper-7

  • question_answer
    In two surfaces of a lens (shown below) \[{{R}_{1}}\] and \[{{R}_{2}}\] are both 5 cm and is made of a material of refractive index 3/2. The power of the lens such formed is

    A)  0                                            

    B)  500 D

    C)  20 D                                     

    D)  \[\infty \]

    Correct Answer: A

    Solution :

    Len's maker's formula is \[\frac{1}{f}=P=({{\mu }_{g}}-1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] \[{{R}_{1}}\] and \[{{R}_{2}}\] are both negative by sign convention. As they are equal \[P=0\].


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