question_answer

The relation between\[{{v}_{1}}\]and\[{{v}_{2}}\]is

A)  \[{{v}_{1}}=\frac{{{v}_{2}}}{\sin \theta }\]                            

B)  \[{{v}_{1}}={{v}_{2}}\]

C)  \[{{v}_{2}}=\frac{{{v}_{1}}}{\sin \theta }\]         

D)  \[d{{v}_{1}}={{v}_{2}}\cos \theta \]

Correct Answer: C

Solution :

\[\sin \theta =\frac{AC}{AB}\] \[\sin \theta =\frac{dY}{dX}\] Differentiate above expression for constant\[\theta \] \[\sin \theta =\frac{{{v}_{1}}}{{{v}_{2}}}\] \[{{v}_{2}}=\frac{{{v}_{1}}}{\sin \theta }\]