A) \[T=2\pi \sqrt{\frac{mg}{x(M+m)}}\]
B) \[T=2\pi \sqrt{\frac{(M+m)x}{mg}}\]
C) \[T=\frac{\pi }{2}\sqrt{\frac{mg}{x(M+m)}}\]
D) \[T=2\pi \sqrt{\frac{M+m}{mg}}\]
Correct Answer: B
Solution :
Let elongation in spring is \[{{x}_{0}}\] when M is suspended, then \[Mg=k{{x}_{0}}\] \[(M+m)g=K({{x}_{0}}+x)\Rightarrow kx=mg\] Time period of combined mass,\[T=2\pi \sqrt{\frac{M+m}{K}}\]\[\Rightarrow \]\[T=2\pi \sqrt{\frac{(M+m)x}{mg}}\]
You need to login to perform this action.
You will be redirected in
3 sec
