A) \[\frac{\pi }{3\omega }\]
B) \[\frac{3\pi }{\omega }\]
C) \[\frac{\pi }{6\omega }\]
D) \[\frac{2\pi }{3\omega }\]
Correct Answer: D
Solution :
As we known that velocity of image is 2 times of velocity of object \[\Rightarrow \] \[{{v}_{0}}=2{{v}_{m}}\] or \[2\,A\omega \,\cos \,\omega t=-2\,A\omega \,\cos \,\,\left( \omega t-\frac{\pi }{3} \right)\] \[\Rightarrow \] \[t=\frac{2\pi }{3\omega }\]
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