A) maximum current through inductor equals \[\frac{{{l}_{0}}}{2}\]
B) maximum current through inductor equals \[\frac{{{C}_{1}}{{l}_{0}}}{{{C}_{1}}+{{C}_{2}}}\]
C) maximum charge on \[\frac{{{C}_{1}}{{l}_{0}}\sqrt{L{{C}_{2}}}}{{{C}_{1}}+{{C}_{2}}}\]
D) maximum charge on \[{{C}_{1}}={{C}_{1}}{{l}_{0}}\sqrt{\frac{L}{{{C}_{1}}+{{C}_{2}}}}\]
Correct Answer: D
Solution :
For the circuit, \[\frac{1}{2}LI_{0}^{2}=\frac{1}{2}\,({{C}_{1}}+{{C}_{2}}){{V}^{2}}\] \[\Rightarrow \] \[V={{\left[ \frac{LI_{0}^{2}}{({{C}_{1}}+{{C}_{2}})} \right]}^{1/2}}\] As, \[{{Q}_{1}}={{C}_{1}}V={{C}_{1}}{{I}_{0}}\,\sqrt{\frac{L}{{{C}_{1}}+{{C}_{2}}}}\]
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