A) charge on \[2\mu F\] capacitor is approximately\[13\mu C\]
B) potential difference across \[3\mu C\]capacitor is approximately 4.3 V
C) potential difference across \[1\mu F\] capacitor is approximately 11 V
D) All of the above
Correct Answer: D
Solution :
Initially, \[{{Q}_{1}}=24\mu \,C\] Finally, \[{{V}_{C}}=\frac{24}{\frac{6}{5}+1}=\frac{24\times 5}{11}\,volt\] \[Q_{3}^{'}=Q_{2}^{'}=\frac{6}{5}\times \frac{24\times 5}{11}13\mu \,C\] (approx) \[Q_{1}^{'}=1\times \frac{24\times 5}{11}=1\,\,1\mu \,C\] (approx) \[V_{1}^{'}=11\] volt \[V_{3}^{'}=\frac{Q_{3}^{'}}{{{C}_{3}}}=\frac{13}{3}=4.3\,\] volt (approx)
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