JEE Main & Advanced Sample Paper JEE Main Sample Paper-46

  • question_answer
    If \[5a+4b+20c=t,\] then the value of \[t\] for which the line \[ax+by+c-1=0\] always passes through a fixed point is

    A)  0                                

    B)  20              

    C)  30                              

    D)  None of these

    Correct Answer: B

    Solution :

     Given, equation of line \[\frac{ax}{c-1}+\frac{by}{c-1}+1=0\] two independent parameters. It can pass through a fixed point, if it contains only one independent. Now, there must be one relation between \[\frac{a}{c-1}\] and \[\frac{b}{c-1}\] independent of a,b and c. So that \[\frac{a}{c-1}\] can be expressed in terms of \[\frac{b}{c-1}\] and straight line contains only one independent parameter. Now, that given relation can be expressed as \[\frac{5a}{c-1}+\frac{4b}{c-1}=\frac{t-20c}{c-1}\] RHS is dependent of \[c,\] if \[t=20\].


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