question_answer

Consider the following reduction reaction \[C{{H}_{3}}C{{H}_{2}}-\overset{\begin{matrix}    O  \\    ||  \\ \end{matrix}}{\mathop{C}}\,-C{{H}_{3}}+LiAl{{H}_{4}}\xrightarrow{O{{H}_{2}}}Alcohol\] the correct statement is

A)  racemic mixture of products is obtained

B)  acerbation reactive intermediate is involved

C)  if hydrolysis is done with \[{{D}_{2}}O\] in place of \[{{H}_{2}}O,\] the product remains the same

D)  if\[LiAl{{D}_{4}}\] is used in place of \[LiAl{{H}_{4}},\,C{{H}_{3}}C{{H}_{2}}(OD)C{{H}_{3}}\] is obtained

Correct Answer: A

Solution :

  Attack of hydride ion \[({{H}^{-}})\] at planar \[(s{{p}^{2}})\] carbonyl carbon is producing a chiral carbon therefore racemic mixture of alcohols would be formed. If \[{{D}_{2}}O\] is used, \[-OD\] group would be formed.