JEE Main & Advanced Sample Paper JEE Main Sample Paper-46

  • question_answer
    The reaction given below shows the peptisation of \[Sn{{O}_{2}}\] precipitate by KOH\[Sn{{O}_{2}}+KOH\xrightarrow{\,}X\] (negatively charged sol). The sol X has formula,

    A)  \[{{K}^{+}}+[Sn{{O}_{2}}]\,{{[Sn{{O}_{3}}]}^{-}}\]

    B)  \[{{K}^{+}}+{{[Sn{{O}_{2}}\cdot x{{H}_{2}}O]}^{-}}OH\]

    C)  \[2\,{{K}^{+}}[Sn{{O}_{2}}]\,SnO_{3}^{2-}\]

    D)  \[{{K}^{+}}+[SnO_{2}^{-1}]\]

    Correct Answer: C

    Solution :

     \[Sn{{O}_{2}}\] is converted into \[SnO_{3}^{2-}\] by \[\overline{O}H\] ions. \[Sn{{O}_{2}}+2O{{H}^{-}}\xrightarrow{\,}\,SnO_{3}^{2-}+{{H}_{2}}O\] \[Sn{{O}_{2}}+SnO_{3}^{2-}\xrightarrow{\,}[Sn{{O}_{2}}]\,SnO_{3}^{2-}\]


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