A) aqueous HCI and heat
B) aqueous NaOH and heat
C) acidified\[KMn{{O}_{4}}\]
D) bromine water
Correct Answer: B
Solution :
\[C{{H}_{3}}CON{{H}_{2}}+NaOH\xrightarrow{\Delta }C{{H}_{3}}COONa+N{{H}_{3}}\]\[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+NaOH\xrightarrow{{}}\] No reaction\[N{{H}_{3}}\] will be liberated in acetamide which will give white fumes on treating with HCl whereas no such gas will be liberated in ethylamine.
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