JEE Main & Advanced Sample Paper JEE Main Sample Paper-46

  • question_answer
    Direction: A potentiometer is device used for measuring emf and internal resistance of a cell. It consists of two circuits one is main circuit in which there is a cell of given emf\[\varepsilon \] and given resistance R which is connected across a wire of length 100 cm having resistance r. Another circuit having unknown emf\[\varepsilon \]and galvanometer. For a given potentiometer if \[\varepsilon '=30\,V,\,\,r=1\Omega \] and resistance R varies with time t given by\[R=2t\]. The jockey can move on wire with constant velocity 10 cm/s and switch S is closed at\[t=0\].
    If jockey starts moving from A at \[t=1\]s, then the balancing point will be obtained at

    A)  \[t=3\,s\]                    

    B)  \[t=5\,s\]

    C)  \[t=4\,s\]                    

    D)  \[t=9\,s\]

    Correct Answer: C

    Solution :

     As,      \[\varepsilon =\frac{3(t-1)}{2t+1}=1\]\[\Rightarrow \]\[t=4\,s\]


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