A) \[[Cu{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\]
B) \[[Ag{{(N{{H}_{3}})}_{2}}]Cl\]
C) \[NO\]
D) \[N{{O}_{2}}\]
Correct Answer: B
Solution :
In \[[Ag\,{{\left( N{{H}_{3}} \right)}_{2}}Cl],\,\,A{{g}^{+}}\] contains d10 configuration. All other contain unpaired electrons so are paramagnetic.
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