A) \[40\,\,k\Omega \]
B) \[4\,k\Omega \]
C) \[200\,\,\Omega \]
D) \[400\,\,\Omega \]
Correct Answer: D
Solution :
The term LED is abbreviation of 'Light Emitting Diode'. It is forward-biased p-n junction with emits spontaneous radiation. Current in the circuit \[=10\,mA=10\times {{10}^{-3}}A\] and voltage in the circuit = 6 - 2 = 4V. From Ohm's law, \[V=IR\] \[\therefore \] \[R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\,\,\Omega \]
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