A) 17
B) 33
C) 50
D) 47
Correct Answer: B
Solution :
The common terms of the given series are 5, 11, 17, ? \[\therefore \] nth term of common sequence \[{{T}_{n}}=5+\,(n-1)\,6=6n-1\] Also, 100th term of the first sequence \[=2\,+(100-1)\,3=299\] and 100th term of the second sequence \[=3+(100-1)2=201\] \[\Rightarrow \] \[{{T}_{n}}\le 201\] \[\Rightarrow \] \[6n-1\le 201\] \[\Rightarrow \] \[n\le 33\frac{2}{3}\] \[\Rightarrow \] \[n=33\]
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