(I)  |
(II) |
(III) |
(IV) \[C{{H}_{3}}-CH=CH-CHO\] |
A) I, II and III
B) II, III and IV
C) I and III
D) I, II, III and IV
Correct Answer: D
Solution :
\[C{{H}_{3}}-CH=CH-CHO\,\,\] \[C{{H}_{2}}=CH-CH=\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H\]
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