A) 103.8%
B) 105.9%
C) 108.8%
D) 110.5%
Correct Answer: C
Solution :
\[{{H}_{2}}{{S}_{2}}{{O}_{7}}+{{H}_{2}}O\xrightarrow{\,}\,2{{H}_{2}}S{{O}_{4}}\] Wt. of oleum sample \[=740-60=680\,g\] To 680 g of \[{{H}_{2}}{{S}_{2}}{{O}_{7}}\]. 60 g of water is added \[\therefore \] To 100 g of \[{{H}_{2}}{{S}_{2}}{{O}_{7}}\] water acidic \[=\frac{60}{680}\times 100=8.82\,g\] \[\therefore \] Strength of oleum = 100 + 8.82 = 108.82%
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