A) \[{{v}_{0}}=R\omega \]
B) \[v={{v}_{0}}\,+R\omega \]
C) \[v={{v}_{0}}-R\omega \]
D) \[v={{v}_{0}}\]
Correct Answer: C
Solution :
This is a direct question based on concept of pure rolling. For no slipping relative velocity of point of contact has to be zero. Here, velocity of the bottom-most point on cylinder is \[{{v}_{0}}-R\omega ,\], and velocity of platform is v. So, from definition of pure rolling \[({{v}_{0}}-R\omega )-v=0\]. Then, for the sphere \[v={{v}_{0}}-R\omega \].
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