question_answer

Identify the correct statement.

A)  \[{{P}_{4}}{{O}_{11}}\]contains peroxide linkages

B)  \[{{P}_{4}}{{O}_{10}}\]contains\[p\pi -d\pi \] back bonding

C)  In \[{{P}_{4}}{{O}_{10}}\] each P atom is bonded to three oxygen atoms

D)  \[{{P}_{4}}{{O}_{10}}\]hydrolyze in water forming phosphorous acid

Correct Answer: B

Solution :

 The structure of \[\therefore \] is as Therefore each P atom is bonded with four oxygen atom. \[t=\frac{v}{a}=\frac{v}{g\mu }\] back bonding is found in the \[\eta =\frac{{{P}_{0}}}{{{P}_{i}}}\] of \[\therefore \]. It forms orthophosphoric acid when hydrolyzed \[\frac{1}{2}\,m{{v}^{2}}=16\,\,J\]