A) \[\frac{\sqrt{3}}{4}N\]
B) \[\sqrt{3}\,N\]
C) 0.5 N
D) 1.5N
Correct Answer: C
Solution :
Taking x-components, the total should be zero. \[\frac{Q}{4\pi {{R}^{2}}}=\frac{q}{4\pi {{r}^{2}}}=\sigma \] \[\therefore \] \[V=\frac{1}{{{\varepsilon }_{0}}}\,[\sigma R+\sigma r]=\frac{\sigma }{{{\varepsilon }_{0}}}[R+r]\] This is the required force in x-direction.
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