A) \[1.3\times {{10}^{-3}}\text{L}\,\text{mo}{{\text{l}}^{-1}}{{\text{s}}^{-1}}\]
B) \[5\times {{10}^{-3}}\text{L}\,\text{mo}{{\text{l}}^{-1}}{{\text{s}}^{-1}}\]
C) \[1.9\times {{10}^{-3}}\text{L}\,\text{mo}{{\text{l}}^{-1}}{{\text{s}}^{-1}}\]
D) \[3.6\times {{10}^{-15}}\text{L}\,\text{mo}{{\text{l}}^{-1}}{{\text{s}}^{-1}}\]
Correct Answer: B
Solution :
At steady state, the rate of destruction of \[{{O}_{3}}\]must equal to rate of its generation ie,\[=\left( \frac{7.2\times {{10}^{-15}}}{60\times 60} \right){{(2\times {{10}^{-8}})}^{2}}.\]From second order rate law \[-\Delta [{{O}_{3}}]/\Delta t=k{{[{{O}_{3}}]}^{2}}\] \[k=(-\Delta [{{O}_{3}}]/\Delta t)/{{[{{O}_{3}}]}^{2}}\] \[{=\left( \frac{7.2\times {{10}^{-15}}}{60\times 60} \right)}/{{{(2\times {{10}^{-8}})}^{2}}}\;\] \[=5\times {{10}^{-3}}L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
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