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JEE Main & Advanced Sample Paper JEE Main Sample Paper-42

  • question_answer
    To a 25 mL HaOa solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 mL of 0.3 N sodium thiosulphate solution. The volume strength of \[{{H}_{2}}{{O}_{2}}\] solution is

    A)  4.444                         

    B)  2.444

    C)  3.344                         

    D)  1.344

    Correct Answer: D

    Solution :

    The number of g-equivalent of \[{{H}_{2}}{{O}_{2}}\] \[\equiv -g\] equivalent of \[{{\text{I}}_{\text{2}}}\] \[\equiv -g\]equivalent of \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\] Strength of 25 mL\[{{H}_{2}}{{O}_{2}}\]solution \[=\frac{20\times 0.3}{25}=0.24N\] \[=0.24\]g-equivalent \[{{O}_{2}}\] \[=0.24\times 5600mL{{O}_{2}}\]at STP in 1 L Volume strength\[=\frac{0.24\times 5600}{1000}=1.344mL\] \[=1.344\]


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