A) 800 mL
B) 200 mL
C) 10 mL
D) zero
Correct Answer: C
Solution :
Noble gases constitute about 1% of the total volume of air. The remaining 99% volume is mainly due to oxygen and nitrogen. When 1 L (1000 mL) of air is passed over heated copper, oxygen is consumed and on further passing over magnesium, nitrogen is consumed according to equations : \[2Cu+{{O}_{2}}\to 2CuO\] \[3Mg+{{N}_{2}}\to M{{g}_{3}}{{N}_{2}}\] In this way about 990 mL of air is consumed. The remaining volume of about 10 mL is due to mainly Ar and other noble gases.
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