question_answer

Direction: Question based on the following paragraph.

Two rods 1 and 2 are released from rest as shown in figure.

Given:\[{{l}_{1}}=4l,{{m}_{1}}=2m,{{l}_{2}}=2l\]and\[{{m}_{2}}=m.\]There is no friction between the two rods. If \[\alpha \]be the angular acceleration of rod 1 just after the rods are released. Then

What is the normal reaction between the two rods at this instant?

A) \[16\sqrt{3}\,ml\alpha \]                     

B) \[\frac{4ml\alpha }{\sqrt{3}}\]

C) \[\frac{32ml\alpha }{3\sqrt{3}}\]                  

D) \[12\sqrt{3}\,ml\alpha \]

Correct Answer: C

Solution :

For rod:\[a=\frac{N(\sqrt{3})}{(2m)(16{{l}^{2}})/3}\] or\[N=\frac{32ml\alpha }{3\sqrt{3}}\]