A) 7.95 eV
B) 17.9 eV
C) 2.96 eV
D) 4.96 Ev
Correct Answer: C
Solution :
The frequency of light wave would be same as that of electric field. The electric field becomes zero 2.4 x 1015 times per second, in one cycle it get zero twice, so frequency becomes\[\frac{2.4\times {{10}^{15}}}{2}=1.2\times {{10}^{15}}\]Hz. So,\[{{K}_{\max }}=hv-\phi \] \[=[4.96-2]eV=2.96eV\]
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