A) Saturation photo current remains same, while stopping potential increases.
B) Saturation photocurrent and stopping potential both decrease.
C) Saturation photocurrent decreases while stopping potential remains same.
D) Saturation photocurrent decreases and stopping potential increases.
Correct Answer: C
Solution :
L As the source of light is taken away, the intensity of light at the location of experiment set up decreases. Photocurrent ex: (Intensity) So, photocurrent decreases. Now, \[{{V}_{0}}=\frac{hc}{{{\lambda }_{0}}e}-\frac{\phi }{e}\] which is independent of intensity.
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