A) 800 K
B) 1600 K
C) 1200 K
D) None of these
Correct Answer: B
Solution :
\[{{v}_{rms}}\propto \sqrt{T}\]\[\Rightarrow \]\[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{v_{2}^{2}}{v_{1}^{2}}=\frac{4{{v}^{2}}}{{{v}^{2}}}=4\]\[\Rightarrow \]\[{{T}_{2}}=4{{T}_{1}}\]\[=4\times 400=1600K\]
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