A) NRT/6
B) 5NRT/2
C) 5.6 NRT
D) 8NRT/3
Correct Answer: A
Solution :
Heat supplied = change in internal energy \[=\Delta U={{U}_{f}}-{{U}_{i}}\] \[{{U}_{f}}=\left( N-\frac{N}{3} \right)\times \frac{5RT}{2}+\frac{N}{3}\times 2\times \frac{3RT}{2}\] \[=\frac{5NRT}{3}+NRT\] \[=\frac{8}{3}NRT\] \[{{U}_{i}}=5\times \frac{NRT}{2}\] \[\Delta Q=\frac{8}{3}NRT-\frac{5NRT}{2}=\frac{NRT}{6}\]
You need to login to perform this action.
You will be redirected in
3 sec
