A) 0.001 mm
B) 0.01 mm
C) 0.10 mm
D) 1.0 mm
Correct Answer: B
Solution :
\[\text{pitch=}\frac{\text{Distance travelled on pitch scale}}{\text{Number}\,\text{of}\,\text{rotation}}\] \[\text{=}\frac{2mm}{4}=0.5mm\]Least count = \[\frac{\text{pitch}}{\text{Number of}\,\text{division}\,\text{on circular scale}}\] \[\frac{0.5mm}{50}=0.01\,mm\]
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