A) \[2-\sqrt{2}\]
B) \[2+\sqrt{2}\]
C) \[\sqrt{2}\]
D) None of these
Correct Answer: A
Solution :
\[\int_{0}^{1.5}{[{{x}^{2}}]dx}=\int_{0}^{1}{0dx}+\int_{1}^{\sqrt{2}}{1}dx\int_{\sqrt{2}}^{1.5}{2dx}\] \[=0+[x]_{1}^{\sqrt{2}}+2[x]_{\sqrt{2}}^{1.5}\] \[=\sqrt{2}-1+2(1.5-\sqrt{2})\] \[=2-\sqrt{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
