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JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    A cell of e.m.f. E is connected across a reistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be

    A) [2(E-V)V]/R                

    B) [2(E-V)/V]R

    C) [(E-V)/V]R                  

    D) (E-V)R

    Correct Answer: C

    Solution :

    Let r be the internal resistance of the cell. Terminal potential difference (V) < EMF of a cell (E). \[V=E-Ir\]or\[r=\frac{E-V}{I}=\left( \frac{E-V}{V} \right)R\]


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